gwakeup: Reduce wake-ups to only first item in queue
We only need to wake up the other side of the GAsyncQueue if we transition from 0 to 1 item in the queue. Otherwise, we can be certain that the other side has received a wakeup and will eventually flush the queue. Part-of: <https://gitlab.gnome.org/GNOME/mutter/-/merge_requests/4007>
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2 changed files with 10 additions and 4 deletions
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@ -1000,8 +1000,11 @@ _clutter_event_push (const ClutterEvent *event,
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event = copy;
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}
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g_async_queue_push (context->events_queue, (gpointer) event);
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g_async_queue_lock (context->events_queue);
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g_async_queue_push_unlocked (context->events_queue, (gpointer) event);
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if (g_async_queue_length_unlocked (context->events_queue) == 1)
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g_main_context_wakeup (NULL);
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g_async_queue_unlock (context->events_queue);
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}
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/**
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@ -599,8 +599,11 @@ meta_thread_impl_queue_task (MetaThreadImpl *thread_impl,
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MetaThreadImplPrivate *priv =
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meta_thread_impl_get_instance_private (thread_impl);
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g_async_queue_push (priv->task_queue, task);
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g_async_queue_lock (priv->task_queue);
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g_async_queue_push_unlocked (priv->task_queue, task);
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if (g_async_queue_length_unlocked (priv->task_queue) == 1)
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g_main_context_wakeup (priv->thread_context);
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g_async_queue_unlock (priv->task_queue);
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}
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gboolean
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